Nuprl Lemma : can-apply-compose-sq 11,40

ABC:Type, g:(A(B + Top)), f:(B(C + Top)), x:A.
can-apply(f o g  ;x) ~ (can-apply(g;x can-apply(f;do-apply(g;x))) 
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ProofTree


Definitionsleft + right, t  T, x:AB(x), P  Q, x:AB(x), s = t, Top, f(a), do-apply(f;x), can-apply(f;x), f o g  , Type

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