Nuprl Lemma : can-apply-compose-sq
11,40
postcript
pdf
A
,
B
,
C
:Type,
g
:(
A
(
B
+ Top)),
f
:(
B
(
C
+ Top)),
x
:
A
.
can-apply(
f
o
g
;
x
) ~ (can-apply(
g
;
x
)
can-apply(
f
;do-apply(
g
;
x
)))
latex
ProofTree
Definitions
left
+
right
,
t
T
,
x
:
A
B
(
x
)
,
P
Q
,
x
:
A
.
B
(
x
)
,
s
=
t
,
Top
,
f
(
a
)
,
do-apply(
f
;
x
)
,
can-apply(
f
;
x
)
,
f
o
g
,
Type
origin